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  1. c++ - What is "operator<<" called? - Stack Overflow

    Apr 11, 2011 · I know the names of most of the operators but not sure what operator<< and operator>> are called. i.e. operator= () // the assignment operator operator== () // the equality …

  2. C# 'or' operator? - Stack Overflow

    Jan 18, 2014 · C# supports two boolean or operators: the single bar | and the double-bar ||. The difference is that | always checks both the left and right conditions, while || only checks the …

  3. What is the Java ?: operator called and what does it do?

    Others have answered this to reasonable extent, but often with the name "ternary operator". Being the pedant that I am, I'd like to make it clear that the name of the operator is the conditional …

  4. AND OR order of operations - Stack Overflow

    May 29, 2013 · In the normal set of boolean connectives (from a logic standpoint), and is higher-precedence than or, so A or B and C is really A or (B and C). Wikipedia lists them in-order. …

  5. sql - Oracle " (+)" Operator - Stack Overflow

    Oct 26, 2010 · It should also be noted that even though the (+) works, Oracle recommends not using it: Oracle recommends that you use the FROM clause OUTER JOIN syntax rather than …

  6. Logical operators ("and", "or") in Windows batch - Stack Overflow

    Jan 26, 2010 · How would you implement logical operators in Windows batch files?

  7. Understanding The Modulus Operator - Stack Overflow

    Jul 8, 2013 · I understand the Modulus operator in terms of the following expression: 7 % 5 This would return 2 due to the fact that 5 goes into 7 once and then gives the 2 that is left over, …

  8. What does the !! (double exclamation mark) operator do in …

    I saw this code: this.vertical = vertical !== undefined ? !!vertical : this.vertical; It seems to be using !! as an operator, which I don't recognize. What does it do?

  9. c++ - What is the difference between the dot (.) operator and ...

    foo->bar() is the same as (*foo).bar(). The parenthesizes above are necessary because of the binding strength of the * and . operators. *foo.bar() wouldn't work because Dot (.) operator is …

  10. css selectors - CSS "and" and "or" - Stack Overflow

    May 9, 2010 · Learn about CSS selectors, including how to use "and" and "or" for efficient styling on Stack Overflow.